Homework Assignment #5Date :Submitted to :Submitted by
:Solution:Header joists:Perimeter of the house= 2(35 + 25 ) =
120Length of the interior walls= 9.5 + 5.5 + 14.25 + 13 + 3 + 19.5
+ 15.5 + 3.75 + 9 = 93Double joist as the header and under the
interior walls needed so the total length of the joistunder walls =
2 (120 + 93 ) = 426Joist @a 12 oc from the North to South excluding
headers= 25 1 = 24Length of each is 35So the total length= 24 35 =
840Total length of joist needed= 840 + 426 = 1266Let the length of
each lumber be 2 x 6 lumber be 12So number of lumber required for
the joist=126612= 105.5 106 lumbersAns.NowNumber of board feet for
each lumber =261212= 12 BFSo quantity of lumber in board feet = 106
12 BF = 1272 BFSolution.Length of each rafter :x19Given ratio is
4_12So4=1912=193, = 192 +Number of rafters: = 2 ( + 1)Here, length
= 44 and spacing is 24 i.e. 2192 = 20.0277 20 32AnsTherefore,
number of rafters= 2 (442+ 1) = 46Hence, 46 rafters of length 20 ft
are required.Solution:Total perimeter of the house = 2(35 + 25 ) =
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